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A cart moves along a track at a velocity of 3.5 cm/s. When a force is applied to the cart, its velocity increases to 8.2 cm/s. If it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? Round your answer to the nearest tenth. cm/s2

Respuesta :

carlosego
The first thing we are going to do for this case is write the equations of movement of the car.
 We have then:
 vf = a * t + vo
 Substituting values:
 8.2 = a * (1.5) + (3.5)
 Clearing the acceleration we have:
 a = (8.2-3.5) / (1.5)
 a = 3.1 m / s ^ 2
 Answer: 
 the acceleration of the cart is: 
 a = 3.1 m / s ^ 2
faithreneetice

Answer:

3.1cm/s^2

Explanation:

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