Respuesta :

cruz1277p5c9lk
The net effective resistance of 10-ohms and 4-ohms 
in series is 14 ohms.

The current in the series loop is  I = E/R = 42V/14-ohms = 3 amperes.

Answer : The magnitude of the current is, 3 ampere

Solution :

In a series circuit, the total resistance will be,

[tex]R=R_1+R_2[/tex]

[tex]R=10\Omega +4\Omega =14\Omega[/tex]

Using coulomb's law,

[tex]V=I\times R\\\\I=\frac{V}{R}[/tex]

where,

V = voltage = 42 V

I = electric current

R = resistance = 14 ohms

Now put all the given values in the above formula, we get

[tex]I=\frac{42V}{14\Omega}=3ampere[/tex]

Therefore, the magnitude of the current is, 3 ampere