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Suzy likes to mix and match her 3 necklaces, 2 bracelets, and 6 hats. The colors are listed in the table. On Monday, she randomly picks a bracelet, a necklace, and a hat. What is the probability of Suzy choosing a red bracelet and silver hat? NECKLACE COLORS: RED ,GREEN ,GOLD BRACELET COLORS: RED AND BLACK HAT COLORS: SILVER, YELLOW, GREEN, GOLD, BLACK, AND WHITE A. one-half B. one-fourth C. start fraction 1 over 6 end fraction D. start fraction 1 over 12 end fraction

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Kalahira
Answer: Option D. 1/12

We have:
3 Necklaces (red, green, and gold)
2 Bracelets (red and black)
6 hats (silver, yellow, green, gold, black, and white)

The number total of combinations is:
C=3x2x6→C=36 possible combinations

What is the probability of Suzy choosing a red bracelet and silver hat?
Possible combinations with a red bracelet and silver hat:
C1=1 (red bracelet) x 1 (silver hat) x 3 (necklaces: red, green, and gold)
C1=3 possible combinations with a red bracelet and silver hat

Probability of Suzy choosing a red bracelet and silver hat: P=C1/C
P=3/36

Simplifying the fraction dividing the numerator and the denominator by 3:
P=(3/3) / (36/3)
P=1/12

Answer: The probability of Suzy choosing a red bracelet and silver hat is 1/12

Answer:

The probability of Suzy choosing a red bracelet and silver hat is 1/12

Step-by-step explanation:

Each one of the red, green, and gold necklace have a probability of 1/3.

Each one of the red and black bracelet have a probability of 1/2.

Each one of the silver, yellow, green, gold, black, and white hat have a probability of 1/6.

Hence, the probability of Suzy choosing a red bracelet and silver hat becomes:

[tex]\frac{1}{2}*\frac{1}{6} =\frac{1}{12}[/tex]

So, the answer is 1/12.

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