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An air mass of volume 6.5 x 10 to the fifth L starts at sea level, where the pressure is 775 mm HG. It rises up a mountain where the pressure is 622 mm HG. Assuming no change in temperature, what is the volume of the air mass?

Respuesta :

From Boyle's law the volume of a fixed mass of a gas is inversely proportional to temperature at constant absolute temperature.
Thus, Vα1/P
    = V = k/P where k is a constant
P1V1=P2V2
Therefore; V2 = P1V1/P2
                       = ( 6.0 ×10^-5 × 775) /622
                       = 7.476 × 10^-5 L
Hence, the new volume of the air mass is 7.476 × 10^-5 L

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