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Find the angle of refraction for a ray of light that enters a bucket of water (n = 1.333) from air at an angle of 17.0◦ to the normal. answer in units of ◦

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nicholasudoye
if the object, ends up with a positive charge, then it is missing electrons. if it is missing electrons, then it must have been removed form the object during the rubbing process.
Eduard22sly

The angle of refraction for the ray of light that enters the bucket of water at an angle of 17° is 12.7°

Snell's law

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

  • i is the angle of incidence
  • r is the angle of refraction

How to determine the refracted angle

From the question given above, the following data were obtained:

  • Index of refraction (n) = 1.333
  • Angle of incidence (i) = 17°
  • Angle of refraction (r) =?

n = Sine i / Sine r

1.333 = Sine 17 / Sine r

Cross multiply

1.333 × Sine r = Sine 17

Divide both side by 1.333

Sine r = Sine 17 / 1.333

Sine r = 0.2193

Take the inverse of Sine

r = Sine¯¹ 0.2193

r = 12.7°

Learn more about Snell's law:

https://brainly.com/question/25758484

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