Respuesta :
Looks to me like C and O are virtually equal and H is double those, so:
CH_20, which is the empirical formula for carbohydrates.
CH_20, which is the empirical formula for carbohydrates.
Answer: The empirical formula for the given compound is [tex]CH_2O[/tex]
Explanation:
We are given:
Moles of carbon = [tex]8.33\times 10^{-2}mol[/tex]
Moles of hydrogen = 0.167 moles
Moles of oxygen = [tex]8.32\times 10^{-2}mol[/tex]
To formulate the empirical formula, we need to follow some steps:
- Step 1: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is [tex]8.32\times 10^{-2}[/tex] moles.
For Carbon = [tex]\frac{8.33\times 10^{-2}}{8.32\times 10^{-2}}=1[/tex]
For Hydrogen = [tex]\frac{0.167}{8.32\times 10^{-2}}=2.01\approx 2[/tex]
For Oxygen = [tex]\frac{8.32\times 10^{-2}}{8.32\times 10^{-2}}=1[/tex]
- Step 2: Taking the mole ratio as their subscripts.
The ratio of C : H : O = 1 : 2 : 1
Hence, the empirical formula for the given compound is [tex]CH_2O[/tex]
