The junior class has 50 students. Twenty-five students take only french, 15 take only Latin, and 10 take both. If a student is chosen at random from the class, what is the probability that the student takes latin?

A.)1
B.)1/2
C.)
1/4

There are 15 students who take Latin, and 10 students who take both.
Therefore:
15+10 =25 total students taking Latin
25students / 50 total students = 1/2

The answer is 1/2.

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JeanaShupp JeanaShupp · Answer 2 · 2019-04-05T21:26:09+02:00

Answer: B ) [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given: The number of students in junior class n(S)= 50

The number of students take only Latin n(L-F)= 15

The number of students take only French n(F-L)=25

The number of students take both = n(F∩L)=10

The number of students take Latin n(L)=n(L-F)+n(F∩L)=15+10=25

Therefore, the probability that the student takes Latin is given by :-

[tex]\text{Probability(Latin)}=\frac{\text{number of students take latin}}{\text{Total students}}\\\\=\frac{25}{50}=\frac{1}{2}[/tex]

The junior class has 50 students. Twenty-five students take only french, 15 take only Latin, and 10 take both. If a student is chosen at random from the class, what is the probability that the student takes latin? A.)1 B.)1/2 C.) 1/4

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The junior class has 50 students. Twenty-five students take only french, 15 take only Latin, and 10 take both. If a student is chosen at random from the class, what is the probability that the student takes latin?

A.)1
B.)1/2
C.)
1/4