Respuesta :
let sandwiches and drinks be s and d resp so according to the question,
by 1st case,
6s + 4d = 53
or, d = (53-6s)/4
again by 2nd case,
4s + 6 d = 47
4s + 6(53-6s)/4 = 47
or, (8s +159-18s)/2=47
or 159-10s = 94
or 65 =10s
or, s = $6.5
by 1st case,
6s + 4d = 53
or, d = (53-6s)/4
again by 2nd case,
4s + 6 d = 47
4s + 6(53-6s)/4 = 47
or, (8s +159-18s)/2=47
or 159-10s = 94
or 65 =10s
or, s = $6.5
We want to find and solve a system of equations to find the cost of one sandwich.
Each sandwich costs $6.50
We can start by defining the variables:
x = price of a sandwich
y = price of a drink.
Then from the given information we can write the equations:
6*x + 4*y = $53
4*x + 6*y = $47
We want to solve this for x, then we need to isolate y in one of the equations. Isolating y in the second equation we get:
y = ($47 - 4*x)/6
Now we can replace this in the other equation and solve it for x:
6*x + 4*($47 - 4*x)/6 = $53
6*x + $31.33 - (16/6)*x = $53
(20/6)*x = $53 - $31.33 = $21.67
x = (6/20)*$21.67 = $6.50
Each sandwich costs $6.50
If you want to learn more, you can read:
https://brainly.com/question/12895249