Respuesta :

altavistard
the easiest way in which we can find the vertex is to rewrite the given y=2x^2-8x+6 in the form y-k =a(x-h)^2, where (h,k) is the vertex.  

y=2x^2-8x+6 can be rewritten as   y = 2(x^2 - 4x                 ) + 6

Completing the square,   y = 2(x^2 - 4x +4 - 4                ) + 6

Then y = 2(x-2)^2 - 2.  Comparing this to a(x-h)^2, we see that h=2 and k=2.  Thus the vertex is at (2, 2).

Answer:

The vertex is [ 2, 6]

Step-by-step explanation:

To find the vertex, all we need to do is to find;

[-b/2a  ,    f(-b/2a)]

From the equation;

y=2x²-8x+6

comparing the above equation by the standard equation

y = ax² + bx + c

a = 2  b =  -8  and c = 6

We can now proceed to insert the values

x = -b/2a  =  8/2(2)    = 8/4 = 2

Next is to find f(-b/2a)

To find  f(-b/2a), we are going to replace x by our value of -b/2a =2  

f(x) = 2x²-8x+6

f (-b/2a) = 2(2)² -8(2) + 6

               =2(4) - 8(2) + 6

               =8 - 8 + 6

               =6

Therefore the vertex is [ 2, 6]

Otras preguntas