Respuesta :

We are given

sequence is 2 , 4 , 8 ,16 , 32 , .....

Firstly , we will check whether it is geometric sequence

Checking geometric sequence:

We will find common ratio between successive terms

and then we check whether they are equal

r1=(second term)/(first term)

[tex] r_1=\frac{4}{2}=2 [/tex]

r2=(third term)/(second term)

[tex] r_2=\frac{8}{4}=2 [/tex]

r3=(fourth term)/(third term)

[tex] r_3=\frac{16}{8}=2 [/tex]

r4=(fifth term)/(fourth term)

[tex] r_4=\frac{32}{16}=2 [/tex]

we can see that all four ratios are same

[tex] r_1=r_2=r_3=r_4=2 [/tex]

so, this is geometric sequence

Calculation of general term:

We got

common ratio is

[tex] r=2 [/tex]

Let's assume

number of terms is n

first term is 2

[tex] a_1=2 [/tex]

now, we can use formula

[tex] a_n=a_1 (r)^{n-1} [/tex]

we can plug values

and we get

[tex] a_n=2(2)^{n-1} [/tex]

[tex] a_n=2^1(2)^{n-1} [/tex]

[tex] a_n=(2)^{n-1+1} [/tex]

[tex] a_n=(2)^{n} [/tex]..................Answer


Answer:

a1: 2     r1: 2

Step-by-step explanation

just did it on edge :)

the answer for the second part is the 1st and 4th formulas