Respuesta :
l = 10
L- the total vertical distance
L = l+(l/2+l/4+l/8+l/16)*2 = 2*l+7/8*l=20+8.75=28.75m
L- the total vertical distance
L = l+(l/2+l/4+l/8+l/16)*2 = 2*l+7/8*l=20+8.75=28.75m
Answer:
Distance covered by the ball = 28.75 meters
Step-by-step explanation:
A ball is dropped from a height of 10 meters.
Each time it bounces 50% of the previous height.
Distance covered by the ball when dropped from a height before 1st bounce = 10 meters
Ball bounced back after 1st bounce and covered a 50% distance of 10 meters = 5 meters
Again this ball goes down and covers distance before 2nd bounce = 5 meters
Now third time the ball bounced back and came down, so distance covered = 2.5 + 2.5 = 5 meters
In 4th bounce ball bounced back and came down, so distance covered = 2×1.25 = 2.5 meters
Similarly in 5th bounce distance covered by the ball = [tex]\frac{1.25}{2}\times 2=1.25[/tex] meters
Total distance covered = 10 + 10 + 5 + 2.5 + 1.25
= 28.75 meters
Therefore, distance covered by the ball will be 28.75 meters.