The area of rectangle ABCD which is graphed in the coordinate plane with vertices A(3, -2), B(6, -2), C(6, 5), and D(3, 5) is 21 unit².
What is the area of a rectangle?
Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,
[tex]A=a\times b[/tex]
Here, (a)is the length of the rectangle and (b) is the width of the rectangle.
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3, -2), B(6, -2), C(6, 5), and D(3, 5).
The shortest distance(length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
[tex]D = \sqrt{(x-p)^2 + (y-q)^2} \: \rm units.[/tex]
The distance from A to B is the length of the rectangle. The distance of line segment AB is,
[tex]W= \sqrt{(3-6)^2 + (-2-(-2))^2}\\W = \sqrt{(-3)^2 + (0)^2}\\W=\sqrt{9}\\W=3\rm\; units[/tex]
The distance from B to C is the width of the rectangle. The distance of line segment BC is,
[tex]L = \sqrt{(6-6)^2 + (-2-5)^2}\\L = \sqrt{(0)^2 + (-7)^2}\\L=\sqrt{49}\\L=7\rm\; units[/tex]
Thus, the area of rectangle ABCD is,
[tex]A=7\times3\\A=21\rm\; unit^2[/tex]
Hence, the area of rectangle ABCD which is graphed in the coordinate plane with vertices A(3, -2), B(6, -2), C(6, 5), and D(3, 5) is 21 unit².
Learn more about the area of rectangle here;
https://brainly.com/question/11202023
#SPJ3
