The given equation of line is
[tex] y=3x-3 [/tex]
Which is of the form
[tex] y = mx +b [/tex]
Where m is the slope which is 3 here.
And slope of parallel lines are equal. So slope of the required line is 3 too .
Now we use slope intercept form, and plug the values of the slope and the given point and solve for b, that is
[tex] 1=3(-1)+b
\\
1 = -3+b
\\
1+3 = b
\\
b=4 [/tex]
So we have m =3 and b=4. Therefore required equation of line is
[tex] y = 3x+4 [/tex]
