What is the measure of an exterior angle of a regular 13-sided polygon? Enter your answer as a decimal in the box. Round to the nearest tenth of a degree.

Every exterior angle is 360. You would divide 360 by the number of sides. Looks like 360/13. Which gives you 27.6923076923. Round up to the tenth and you get the answer.

=27.7

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deepakrai138 deepakrai138 · Answer 2 · 2021-12-28T13:04:43+01:00

The measure of an exterior angle of a regular 13-sided polygon is 27.7 Degrees.

Given sides of regular polygon is 13.

Since the polygon is regular it means all the sides of polygon is equal.

We know that,

The sum of exterior angles in a regular polygon is always equal to 360 degrees. Therefore, for all regular polygons, the measure of one exterior angle is equal to 360 divided by the number of sides in the polygon.

So, the measure of one exterior angle (say [tex]x[/tex]) in 13-sided polygon will be,

[tex]x=\frac{360}{13}[/tex]

[tex]x=27.692[/tex]

On rounding off to the nearest tenth it is 27.7 Degrees.

Hence, the measure of an exterior angle of a regular 13-sided polygon is 27.7 Degrees.

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