Respuesta :
With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.
If
80% --- 50000 J
100% --- ?? J
Solution:
Input work = (100/80)*500000 J = 62500 J
If
80% --- 50000 J
100% --- ?? J
Solution:
Input work = (100/80)*500000 J = 62500 J