Answer: The molarity of the diluted solution will be 0.636 M
Explanation:
To calculate the molarity of the diluted solution, we use the equation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the concentrated solution
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of diluted solution
We are given:
[tex]M_1=6M\\V_1=26.5mL\\M_2=?M\\V_2=250mL[/tex]
Putting values in above equation, we get:
[tex]6\times 26.5=M_2\times 250\\\\M_2=0.636M[/tex]
Hence, the molarity of the diluted solution will be 0.636 M
The molarity of the diluted solution made by diluting 26.5 mL of 6.00 M HNO₃ to a volume of 250 mL is 0.636 M
From the question given above, the following data were obtained:
Volume of stock solution (V₁) = 26.5 mL
Molarity of stock (M₁) = 6.00 M
Volume of diluted solution (V₂) = 250 mL
The molarity of the diluted solution of HNO₃ can be obtained as follow:
6 × 26.5 = M₂ × 250
159 = M₂ × 250
Divide both side by 250
M₂ = 159 / 250
Thus, the molarity of the diluted solution of HNO₃ is 0.636 M
Learn more: https://brainly.com/question/9101646?
