Respuesta :

transitionstate
Formula for Molarity is given as,

                                      Molarity  =  moles / Volume of Solution in L     ----(1)
Also,
                                         Moles  =  mass / M.mass

Putting value of mole in eq. 1,

                                      Molarity  =  (mass / M.mass) / Vol
Solving for mass,
                                          Mass  =  Molarity × M.mass × Vol
Putting Values,
                                          Mass  =  0.15 mol/L × 40 g/mol × 0.5 L

                                          Mass  =  3 g
Result:
            Weight 3 g of NaOH, add it to a 500 ml volumetric flask, and add distilled water to the point of 500 ml. The resulting solution will be 0.15 M.
Eduard22sly

The approximate mass of NaOH required to prepare 500 mL of a 0.15 M NaOH solution is 3 g

We'll begin by calculating the number of mole of NaOH in the solution. This can be obtained as follow:

Volume = 500 mL = 500 / 1000 = 0.5 L

Molarity of NaOH = 0.15 M

Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.15 × 0.5

Mole of NaOH = 0.075 mole

Finally, we shall determine the approximate mass of NaOH. This can be obtained as follow:

Mole of NaOH = 0.075 mole

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.075 × 40

Mass of NaOH = 3 g

Therefore, the approximate mass of NaOH required to prepare the solution is 3 g

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