Respuesta :
Because t is given in years and 1.08 = 1 + 0.08, the annual percent increase
is 8%.
To find the monthly percent increase that gives an 8% annual increase,
use the fact that
t = [tex] \frac{1}{12} * 12 t[/tex]
and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.
[tex] 1.08^{t} = 1.08^{(1/12)(12t)} = (1.08^{1/12}) ^{12t} = 1.0064634^{12t} [/tex]
is 8%.
To find the monthly percent increase that gives an 8% annual increase,
use the fact that
t = [tex] \frac{1}{12} * 12 t[/tex]
and the properties of exponents to rewrite the
model in a form that reveals the monthly growth rate.
[tex] 1.08^{t} = 1.08^{(1/12)(12t)} = (1.08^{1/12}) ^{12t} = 1.0064634^{12t} [/tex]
Answer:
(1.006)^12t
Step-by-step explanation:
I just did it on UsaTestPrep.
(1.08^1/12)^12t ≈ (1.006)^12t
Hope this helps!