Respuesta :

cosine theorem
3²=5²+7²-2*5*7*cosT
9=25+49-70*cosT
9-74=-70 *cos T
-65/(-70)= cos T
T = arccos (65/70)≈22°

Riia

In this question, we use law of cosine which is

[tex] RS^2 = RT^2 + ST^2 -2(RT)(ST) cos T [/tex]

Substituting the given values of RS,RT, ST , we will get

[tex] 3^2 = 5^2 + 7^2 -2(5)(7) cos T
\\
9 = 25 +49 - 70 cos T [/tex]

[tex] cos T = \frac{65}{70} [/tex]

Taking inverse cosine on both sides

[tex] T = cos^{-1} ( \frac{65}{70}) [/tex]

[tex] T = 22 [/tex]


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