In this question , it is given that , the width of a rectangle is 6 2/3 inches.The length of the rectangle is twice its width.
First we need to convert mixed fraction to improper fraction.
[tex] width = 6 \frac{2}{3} = \frac{20}{3} [/tex]
And length is twice of width, so length is
[tex] length = 2* \frac{20}{3} = \frac{40}{3} [/tex]
The formula of perimeter is two times the sum of length and width.
[tex] Perimeter = 2(\frac{20}{3} + \frac{40}{3} ) = 2( \frac{60}{3}) = 2*20 = 40 inches [/tex]
