WILL MARK BRAINLEIST!!! 30 POINTS!!!!!!!

Choose the correct list of molecule labels (in the order 1, 2, 3, 4) in the dehydration synthesis process shown below.

The image represents the dehydration synthesis of a molecule (C12H22O11) with numbered blanks for the labels of the molecules in the process. The first molecule is a 6 sided carbon ring with an oxygen at one corner of the ring and 4 –OH groups and a carboxyl group (-COOH) branching from the carbons in the ring. The second molecule is a 5 sided carbon ring with an oxygen at one corner of the ring and 3 –OH groups and 2 carboxyl groups (-COOH) branching from the carbons in the ring. Arrows show that one hydrogen from the 6-sided carbon ring's OH group and an OH group from the 5-sided carbon ring combine to form a third molecule, left blank, and a fourth molecule which combines the two rings by sharing an oxygen.

1 Sucrose, 2 galactose, 3 water, 4 fructose
1 Galactose, 2 glucose, 3 water, 4 fructose
1 Glucose, 2 fructose, 3 water, 4 sucrose
1 Fructose, 2 glucose, 3 water, 4 sucrose

Respuesta :

According to the explanation of the image, the right answer is 1 Sucrose, 2 galactose, 3 water, 4 fructose.

The undeveloped chemical formula of sucrose is C12H22O11.

Galactose is an aldo-hexose. It can take the cyclic conformation of five carbons plus an oxygen, with a lateral carbon.

Fructose is a ceto-hexose. It can take the cyclic conformation of four carbons plus one oxygen, with two lateral carbons.

ATal

Answer:

According to the explanation of the image, the right answer is 1 Sucrose, 2 galactose, 3 water, 4 fructose.

Explanation:

The undeveloped chemical formula of sucrose is C12H22O11.

Galactose is an aldo-hexose. It can take the cyclic conformation of five carbons plus an oxygen, with a lateral carbon.

Fructose is a ceto-hexose. It can take the cyclic conformation of four carbons plus one oxygen, with two lateral carbons.