Answer:
The factored form of [tex]6x^2+11x-10[/tex] is [tex]\left(3x-2\right)\left(2x+5\right)[/tex]
Step-by-step explanation:
To factor the expression [tex]6x^2+11x-10[/tex] you must,
Break the expression into groups
[tex]6x^2+11x-10=\left(6x^2-4x\right)+\left(15x-10\right)[/tex]
Factor out [tex]2x[/tex] from [tex]6x^2-4x[/tex]
[tex]6x^2-4x=2x\left(3x-2\right)[/tex]
Factor out [tex]5[/tex] from [tex]15x-10[/tex]
[tex]15x-10=5\left(3x-2\right)[/tex]
Thus,
[tex]6x^2+11x-10=2x\left(3x-2\right)+5\left(3x-2\right)\\\\\mathrm{Factor\:out\:common\:term\:}3x-2\\\\6x^2+11x-10= \left(3x-2\right)\left(2x+5\right)[/tex]
