Answer: 92.74 m
we need to find the displacement.
[tex]45 cos 60 = 22.5 m\\ 45 sin 60 = 38.97 m\\[/tex]
adding vertical components to
gether:
[tex]38.97 m+51 m= 89.97 m[/tex]
horizontal component:
[tex]22.5 m[/tex]
For displacement, we need to calculate the resultant of above two:
[tex] R=\sqrt {a^2 + b^2} [/tex]
[tex] R= \sqrt {22.5^2+89.97^2} \\ \Rightarrow R=\sqrt {8601.05}=92.74 m[/tex]
Hence, you would be 92.74 m away from home.
