Respuesta :
toichiometry time! Remember to look at the equation for your molar ratios in other problems.
31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag 6851.65⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ → ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ = 107.9 g Ag ∅ | 63.5 g Cu | 1 mol Cu | 1 mol Ag 63.5
There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag 6851.65⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ → ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ = 107.9 g Ag ∅ | 63.5 g Cu | 1 mol Cu | 1 mol Ag 63.5
There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
Answer: 107.9 grams of Ag will be produced.
Explanation: Reaction of Copper metal with Silver nitrate follows:
[tex]Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)[/tex]
As [tex]AgNO_3[/tex] is present in excess, therefore Copper metal is considered as the limiting reagent because it limits the formation of product.
We are given 31.75 grams of Copper metal are used in the reaction
Molar mass of Copper = 63.5 g/mol.
Moles can be calculated by:
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
[tex]\text{Moles of Copper}=\frac{31.75g}{63.5g/mol}=0.5moles[/tex]
From the reaction, we see that
For every 1 mole of Copper metal, 2 moles of Ag are produced.
For 0.5 moles of Copper, moles of Ag produced = [tex]\frac{2}{1}\times 0.5[/tex]
Moles of Ag produced = 1 mole
Mass of Ag produced can be calculated by using equation 1.
Mass of Ag produced will be = Moles × Molar mass
Molar mass of Ag = 107.9 g/mol
[tex]\text{Mass of Ag produced}=1\times 107.9g/mol[/tex]
Mass of Ag produced = 107.9 g/mol
