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Find the approximate solution of this system of equations. y=x^2+5x+3 y=square root2x+5
A.) (2.1, 0.2)
B.) (-0.2, 2.1)
C.) (-2.1, 0.2)
D.) (0.2, 2.1)

Respuesta :

calculista
we have that
y=x²+5x+3
y=√(2x+5)

using a graph tool
see the attached figure

the solution is 
x=-0.175
y=2.156

therefore

the answer is the option
B.) (-0.2, 2.1)
Ver imagen calculista

Answer:

[tex]x=-1.216 and x= -0.175[/tex]

Step-by-step explanation:

Given is a system of equations in x. One quadratic and other square root.

1) [tex]y=x^2+5x+3[/tex]

2) [tex]y=\sqrt{2x+5}[/tex]

Subtracting 2 from 1 we get

[tex]x^2+5x+3=\sqrt{2x+5}[/tex]

Square both the sides

[tex]x^4+25x^2+9+10x^3+30x+6x^2 =2x+5\\x^4+10x^3+31x^2+28x+4=0[/tex]

We find that there are only two real roots and they are approximately

x=-1.216 and x= -0.175

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