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Write the equation of the circle with center (−3, −2) and (4, 5) a point on the circle. A) (x + 3)2 + (y + 2)2 = 49
B) (x + 3)2 + (y + 2)2 = 98
C) (x − 3)2 + (y − 2)2 = 49
D) (x − 3)2 + (y − 2)2 = 98

Respuesta :

The general equation of circles is (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center. 1. 2x^2+2y^2=72 =x^2+y^2=36  c: (0,0); r = 62. (x-3)^2+(y-1)^2=4 : c: (3,1); r = 23. (x-5)^2+(y+2)^2=49;  c: (5,-2); r = 74. (y-4)^2+(x-10)^2=64:  c: (4,10); r = 85.(x^2-6x+9)+(y^2+8y+16)=1:  c: (3,-4); r = 16. x^2+12x+y^2-8y=-27 =x^2+12x + 36+y^2-8y+16=-27+36+16=25:  c( -6,4); r = 5

Answer:

b

Step-by-step explanation:

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