Let
A(2,4)
B(8,12)
C (24,0)
we know that
[perimeter of triangle]=AB+BC+AC
step 1
find the distance AB
d=√[(12-4)²+(8-2)²]-----> dAB=√100------> dAB=10 units
step 2
find the distance BC
d=√[(0-12)²+(24-8)²]-----> dBC=√400------> dBC=20 units
step 3
find the distance AC
d=√[(0-4)²+(24-2)²]-----> dAC=√500------> dAC=22.36 units
[perimeter of triangle]=AB+BC+AC------> 10+20+22.36-----> 52.36 units
the answer is
the perimeter of triangle is 52.36 units
