The integers are odd. Let the integers are
[tex] 2n+1, 2n+3 [/tex]
And the given product is 63 .
That is
[tex] (2n+1)(2n+3) = 63
\\
4n^2 + 6n +2n + 3 -63=0
\\
4n^2 +8n -60=0
[/tex]
Dividing whole equation by 4
[tex] n^2 + 2n -15=0
\\
(n+5)(n-3) =0 [/tex]
[tex] n+5=0, n-3=0
\\
n=-5, n=3 [/tex]
When n = -5, numbers are
[tex] 2(-5)+1 , 2(-5)+3 = -9, -7 [/tex]
When n =3, we will get
[tex] 2(3)+1 , 2(3) + 3 = 7, 9 [/tex]
