Answer: The solubility product for the given salt is [tex]1.31\times 10^{-4}[/tex]
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is represented as [tex]K_{sp}[/tex]
Silver carbonate is an ionic compound formed by the combination of 2 silver ions and 1 carbonate ions.
The equilibrium reaction for the ionization of silver carbonate follows the equation:
[tex]Ag_2CO_3(aq.)\rightleftharpoons 2Ag^{+}(aq.)+CO_3^{2-}(aq.)[/tex]
1 mole of silver carbonate produces 2 moles of silver ions and 1 mole of carbonate ion
The expression of [tex]K_{sp}[/tex] for above equation is:
[tex]K_{sp}=[2Ag^+]^2[CO_3^{2-}][/tex]
We are given:
[tex][Ag^+]=(2\times 0.032)=0.064M[/tex]
[tex][CO_3^{2-}]=0.032M[/tex]
Putting values in above equation, we get:
[tex]K_{sp}=(0.064)^2\times 0.032=1.31\times 10^{-4}[/tex]
Hence, the solubility product for the given salt is [tex]1.31\times 10^{-4}[/tex]
