Respuesta :

kenmyna
The  Ksp  expression   for  Zn(CN)2 is  written  as  follows

write  the    equation  for  dissociation

that   is,   
zN(CN)2   ------> Zn 2+(aq)      +   2CN-(aq)


ksp   is  therefore  =  (Zn2+)(  CN-)^2

CN-  is  raised  to  a  power  of  two  since  there  are  two  CN-  ion  in the  equation   above
dsdrajlin

Answer:

Kps = [Zn²⁺].[CN⁻]²

Explanation:

Let's consider the solution of zinc cyanide.

Zn(CN)₂(s) ⇄ Zn²⁺(aq) + 2 CN⁻(aq)

The solubility product (Kps) is the equilibrium constant for this solution, that is, the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients. Only aqueous species are included in the expression of kps.

The Kps is:

Kps = [Zn²⁺].[CN⁻]²

Otras preguntas