Respuesta :

Allysia123
Measure of Hypotaneous = 5√5

And it's already given that b = 2a

By using pythagoras theorem:

a²+ b² = (5√5)²

Let's substitute for b as 2a in above equation we'll get:

a² + (2a)² = (5√5)²

a² + 4a² = 125
5a² = 125
a² = 25
a = √25 = 5


Therefore,
a= 5
and
b = 2a = 2(5) = 10.
The pythagoras theorem is [tex]a^{2} + b^{2} = c^{2}[/tex] where C is the hypotenuse. 

Since a is twice of b, 
a = 2b 

The hypotenuse is C = 5√5. 

Let's put this into the pythagoras equation

[tex]( 2b)^{2} + b^{2} = (5 \sqrt{5})^{2}[/tex]

[tex]5b^{2} = (125)[/tex]

[tex]b^{2} = 25[/tex]

[tex]b=5[/tex]

since we know a=2b, then a = 2(5) 
a=10[tex]since we know a=2b, then a = 2(5) [/tex]



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