Respuesta :
pOH+pH=14
pH=14-pOH=14-3.53=10.47
pH=-log[H⁺]
[H⁺]=10^(-pH)
[H⁺]=10^(-10.47)=3.4*10(^-11)
pH=14-pOH=14-3.53=10.47
pH=-log[H⁺]
[H⁺]=10^(-pH)
[H⁺]=10^(-10.47)=3.4*10(^-11)
We have that h+ concentration is mathematically given as
H^+=8.7e-11
From the question we are told
- What is the h+ concentration for an aqueous solution
- poh = 3.53 at 25 ∘c?
Hydrogen
Generally the equation for poh is mathematically given as
[tex]pOH=-log{OH^-}\\\\Therefore\\\\-log{OH^-}=3.53\\\\ OH=1.15e-4\\\\Hence\\\\H^+=\frac{1.0e-14}{1.15e-4}\\\\[/tex]
- H^+=8.7e-11
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