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Three tanks,A,B,C are used to store oil. Tank A contains 'n' litres of oil. Tank B contains (n+150) litres of oil. Tank C is empty. Oil is pumped from tank A and from tank B into tank C so that all three tanks contain the same amount of oil. 500 litres of oil are pumped from tank A into tank C. work out the value of 'n'.

Respuesta :

Before Transferring oil to Tank C :
Tank A = n
Tank B = n + 150
Tank C = 0

Total = n + n + 150 
Total = 2n + 150

After transferring some oil to Tank C, each of the tank has the same amount.
Each tank = (2n + 150) ÷ 3 = 2/3 n + 50

500ml was transferred from tank A to Tank C:
n - (2/3n + 50) = 500
n - 2/3n - 50 = 500
1/3n = 550
n = 1650 ml

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Answer: The value of n is 1650.
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Check:
Before Transfer: 
Tank A = n = 1650
Tank B = n + 150 = 1650 + 150 = 1800
Tank C = 0

Total = 1650 + 1800 = 3450ml

After transfer:
Each tank = 3450 ÷ 3 
Each tank = 1150

Tank A before transfer = 1650
Tank A after transfer = 1150
1650 - 1150 = 500 (checked)

ashishdwivedilVT

The value of n is 1650 after oil is transferred from Tank A and Tank B to Tank C.

It is given that initially,

Oil in tank A = n

Oil in tank B = n+150

Oil in tank C = 0

Amount of oil transferred to tank C by tank A = 500 litres

Let us say 'x' amount of oil was transferred to tank C from tank B.

The amount of oil left in tank A after transferring 500 litres to tank C = n-500

Amount of oil left in tank B after transferring 'x' litres to tank C = n+150-x

Amount of oil in tank C now = 500+x

Since it is given that all three tanks contain the same amount of oil now. i.e. the new amount of oil in tank A = new amount of oil in tank B

n-500 = n+150-x

x = 650

The new amount of oil in tank B = new amount of oil in tank C

n+150-x = 500+x

n = 350+2x

as x = 500

n= 350+2*650 = 1650

Therefore, the value of n is 1650.

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