The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs. This situation can be represented by a system of two linear equations. One of these equations is given. Write the second equation in the box.

d/3=h

Given : The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs.

To find : Second equation from the situation?

Solution :

We have given,

'h' represent the humans,

'd' represent the dogs.

There must be 1 human to every 3 dogs.

So, One equation is [tex]\frac{d}{3}=h[/tex] (given)

According to question,

There can only be 120 dogs and humans combined.

i.e. The required equation is [tex]d+h=120[/tex]

Therefore, The event space imposes two restrictions on the party are

Equation 1 - [tex]\frac{d}{3}=h[/tex]

Equation 2 - [tex]d+h=120[/tex]