Respuesta :

Answer:

Yes, the ordered pair (0,0) is a solution of the system

Step-by-step explanation:

we have

[tex]y\geq x^{2}+x-4[/tex] ----> inequality A

[tex]y < x^{2} +2x+1[/tex] ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

Verify

For x=0,y=0

Inequality A

[tex]0\geq (0)^{2}+0-4[/tex]

[tex]0\geq -4[/tex] ----> is true

so

The ordered pair satisfy inequality A

Inequality B

[tex]0 < (0)^{2} +2(0)+1[/tex]

[tex]0 < 1[/tex]  ----> is true

so

The ordered pair satisfy inequality B

therefore

The ordered pair (0,0) is a solution of the system

(0,0) is a solution to this system y ≥ x² + x - 4 and y < x² + 2x + 1

Further explanation

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

D = b² - 4 a c

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

An axis of symmetry of quadratic equation y = ax² + bx + c is :

[tex]\large {\boxed {x = \frac{-b}{2a} } }[/tex]

Let us now tackle the problem!

Given:

[tex]y \geq x^2 + x - 4[/tex]

[tex]y \leq x^2 + 2x +1[/tex]

[tex]\texttt{ }[/tex]

If we put the coordinate (0 , 0) into the two inequality above then:

[tex]y \geq x^2 + x - 4[/tex]

[tex]0 \geq 0^2 + 0 - 4[/tex]

[tex]0 \geq - 4[/tex] → true

[tex]\texttt{ }[/tex]

[tex]y \leq x^2 + 2x +1[/tex]

[tex]0 \leq 0^2 + 2(0) +1[/tex]

[tex]0 \leq 1[/tex] → true

[tex]\texttt{ }[/tex]

Since the two inequality values are true when the coordinate is (0,0), then it can be concluded that (0,0) is a solution to this system.

[tex]\texttt{ }[/tex]

Learn more

  • Solving Quadratic Equations by Factoring : https://brainly.com/question/12182022
  • Determine the Discriminant : https://brainly.com/question/4600943
  • Formula of Quadratic Equations : https://brainly.com/question/3776858

Answer details

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

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