Respuesta :

alesasorrell
The equation would be:

-3(-2) ^n-1

-3, 6,-12, 24, 48

so a5=48

Answer:

 the [tex]a_5 =-48[/tex]

Step-by-step explanation:

  • Geometric sequence is written as:  a, ar, ar², ar³,.... where r is common ratio.
  • The general term of geometric sequence is written as [tex]a_n =a_1 r^{n-1}[/tex]

in this question, we need to find the 5th term of geometric sequence

so, we will put n=5,r=-2 and [tex]a_n =-3}[/tex] in [tex]a_n =a_1 r^{n-1}[/tex];

[tex]a_5 =(-3) (-2)^{5-1}[/tex]

[tex]a_5 =(-3) (-2)^{4}[/tex]

[tex]a_5 =(-3) (16)[/tex]

[tex]a_5 =-48[/tex]

Therefore, the [tex]a_5 =-48[/tex]

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