[tex]\bf \textit{Logarithm of rationals}
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log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
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\textit{Logarithm of exponentials}
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log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\
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log\left( \frac{y}{z^9} \right)\implies log(y)-log(z^9)\implies log(y)=9log(z)[/tex]
