If you want to find the length of other leg (AB) you can use Pythagoras
[tex] \sqrt{8 {}^{2} - 4^{2} } \\ = \sqrt{64 - 16} \\ = \sqrt{48} \\ = 4 \sqrt{3} [/tex]
So, the length of other leg is 4√3 cm.
The acute angles are <B and <C (look at my drawing)
sin <B = 8/4= 1/2
<B = 30°
<C = 180°-(30+90)
= 60°
Hope this help!
