The period of the oscillation when the object is then given a slight push and executes is 0.802 seconds.
The time period of the spring is used in spring mass system to find the oscillation of a system who perform simple harmonic motion.
The time period of the spring can be calculated with the following formula.
[tex]T=2\pi\sqrt{\dfrac{m}{k}}[/tex]
Here, (m) is the mass of the spring and (k) is the spring constant. As the gravitational force is balanced by the spring force. Thus, the above formula can also be written as,
[tex]T=2\pi\sqrt{\dfrac{x}{g}}[/tex]
Here, x is the distance of spring from the equilibrium point.
An object of unknown mass m is hung from a vertical spring of unknown spring constant k, and the object is observed to be at rest when the spring has extended by 16 cm or 0.16 m.
Put this value in the above formula,
[tex]T=2\pi\sqrt{\dfrac{0.16}{9.81}}\\T=0.802\rm \;s[/tex]
Thus, the period of the oscillation when the object is then given a slight push and executes is 0.802 seconds.
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