Respuesta :
Given,
Density of gas = 1.653 g/L
Pressure = 746 mm Hg = 0.981 atm
Temperature = 25 degree Celsius or 298 Kelvin
By ideal gas law we know,
PV=nRT
where,
P=Pressure
V=Volume of gas
n= no.of moles
R=Universal gas constant (0.0821)
T= temperature
Now to know the molar mass, we can use following formula;
Molar mass (M) = mass (m)/ no.of moles(n)
or, No.of moles (n)= mass (m)/Molar mass (M)
also, density is related to mass by formula;
Density = Mass(m) * Volume (V)
o
Using the above relationship in ideal gas equation, we have,
P.V= m/M. R.T
P. V. M = mRT
M =m /V * RT/P
Since density = m/V, using the relation we get,
M= Density * RT/P
M= (1.653 g/L * 0.082 atm.L/mol.k * 298K)/0.981 atm
= 41.22 g/mol
Hence the molar mass of the gas is 41.22 g/mol
Density of gas = 1.653 g/L
Pressure = 746 mm Hg = 0.981 atm
Temperature = 25 degree Celsius or 298 Kelvin
By ideal gas law we know,
PV=nRT
where,
P=Pressure
V=Volume of gas
n= no.of moles
R=Universal gas constant (0.0821)
T= temperature
Now to know the molar mass, we can use following formula;
Molar mass (M) = mass (m)/ no.of moles(n)
or, No.of moles (n)= mass (m)/Molar mass (M)
also, density is related to mass by formula;
Density = Mass(m) * Volume (V)
o
Using the above relationship in ideal gas equation, we have,
P.V= m/M. R.T
P. V. M = mRT
M =m /V * RT/P
Since density = m/V, using the relation we get,
M= Density * RT/P
M= (1.653 g/L * 0.082 atm.L/mol.k * 298K)/0.981 atm
= 41.22 g/mol
Hence the molar mass of the gas is 41.22 g/mol
The molar mass of gas is [tex]\boxed{{\text{41}}{\text{.22 g/mol}}}[/tex].
Further Explanation:
An ideal gas is a hypothetical gas that is composed of a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.
Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:
[tex]{\text{PV}} = {\text{nRT}}[/tex] …… (1)
Here,
P is the pressure of the ideal gas.
V is the volume of the ideal gas.
T is the absolute temperature of the ideal gas.
n is the number of moles of gas.
R is the universal gas constant.
The formula to calculate the number of moles of gas is as follows:
[tex]{\text{n}} = \frac{{\text{m}}}{{\text{M}}}[/tex] ...... (2)
Here,
n is the number of moles of gas.
m is the mass of gas.
M is the molar mass of gas.
The formula to calculate the density of the gas is as follows:
[tex]{\rho }} = \frac{m}{V}[/tex] ...... (3)
Here,
[tex]{\rho }}[/tex] is the density of the gas.
m is the mass of gas.
V is the volume of gas.
Rearrange equation (3) to calculate the mass of gas.
[tex]{\text{m}}={\rho V}}[/tex] ...... (4)
Substitute the value of mass from equation (4) in equation (2).
[tex]{\text{n}} = \frac{\rho V}{{M}}}[/tex] ...... (5)
Substitute the value of n from equation (5) in equation (1).
[tex]{\text{P}} = \frac{\rho RT}{{\text{M}}}[/tex] ...... (6)
Rearrange equation (6) to calculate M.
[tex]{\text{M}} = \frac{\rho RT}{{\text{P}}}[/tex] ...... (7)
The density of the gas is 1.653 g/mL.
The pressure of the ideal gas is 746 mm Hg.
The temperature of the ideal gas is [tex]{\text{25}}\;^\circ {\text{C}}[/tex].
The universal gas constant is 0.0821 L atm/K mol.
Substitute these values in equation (7).
[tex]\begin{aligned}{\text{M}}&=\frac{{\left({{\text{1}}{\text{.653 g/mL}}}\right)\left( {0.0821{\text{ L atm/K mol}}}\right)\left({25+27{\text{3}}{\text{.15}}}\right){\text{K}}}}{{\left( {746{\text{ mm Hg}}}\right)\left({\frac{{{\text{1 atm}}}}{{760{\text{ mm Hg}}}}} \right)}} \\&=41.2{\text{216 g/mol}}\\&\approx {\text{41}}{\text{.22 g/mol}}\\\end{aligned}[/tex]
Learn more:
1. How many moles of Cl are present in 8 moles of [tex]{\text{CC}}{{\text{l}}_4}[/tex]? https://brainly.com/question/3064603
2. Calculate the moles of ions in HCl solution: https://brainly.com/question/5950133
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: P, V, n, R, T, ideal gas, pressure, volume, 41.22 g/mol, density, molar mass, 1.653 g/mL, 746 mm Hg, m, M.