Spinner i is divided into four equal sections labeled 2, 3, 4 and 5. spinner ii is divided into five equal sections labeled 1, 3, 5, 7 and 9. if each spinner is spun and the resulting numbers are multiplied, what is the probability that the product is a two-digit even number? express your answer as a common fraction.

The probability is 7/20.

There are 20 outcomes in the sample space:
2(1) 2(3) 2(5) 2(7) 2(9)
3(1) 3(3) 3(5) 3(7) 3(9)
4(1) 4(3) 4(5) 4(7) 4(9)
5(1) 5(3) 5(5) 5(7) 5(9)

Out of these, 14 are two digit products. Out of those 14, only 7 are odd. Thus the probability is 7/20.

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facundo3141592 facundo3141592 · Answer 2 · 2020-04-20T03:58:42+02:00

Answer: The probability is p = 0.35

Step-by-step explanation:

The data is:

Spinner 1 is labeled 2, 3, 4 and 5

Spinner 2 is labeled 1, 3, 5, 7 and 9

then the first spinner has 4 options and the second one has 5 options, so we have a total of 4*5 = 20 possible outcomes of spurning both spinners.

The options where the product is a two-digit even number are:

2*5 = 10

2*7 = 14

2*9 = 18

4*3 = 12

4*5 = 20

4*7 = 28

4*9 = 36

so we have a total of 7 combinations where the product of both numbers is a two-digit number.

The probability of this event happening is equal to the number of combinations where this event happens, divide the total number of combinations, so we have:

P = 7/20 = 0.35