The puck slides about 26 m before coming to rest
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Let's recall Kinetic Energy Formula as follows:
[tex]Ek = \frac{1}{2}mv^2[/tex]
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
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Complete Question:
A hockey puck is given an initial speed of 5.0 m/s. If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide beofre coming to rest? (Solve this problem using conservation of energy in detail.)
Given:
initial speed of the puck = v = 5.0 m/s
coefficient of friction = μ = 0.05
Asked:
distance = d = ?
Solution:
[tex]W = \Delta Ek[/tex]
[tex]fd = \frac{1}{2}mv^2[/tex]
[tex]\mu N d = \frac{1}{2}mv^2[/tex]
[tex]\mu mgd = \frac{1}{2}mv^2[/tex]
[tex]\mu g d = \frac{1}{2}v^2[/tex]
[tex]d = (\frac{1}{2}v^2) \div (\mu g)[/tex]
[tex]d = (\frac{1}{2} \times 5^2) \div (0.05 \times 9.8)[/tex]
[tex]d \approx 26 \texttt{m}[/tex]
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Grade: High School
Subject: Physics
Chapter: Dynamics
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
