Respuesta :
"Time constant" is the time required for an exponentially decaying signal to drop to (its initial value)/e .
But 1/e = 0.367...
So IF the amplitude of this oscillator is decaying exponentially for some crazy reason, then the time constant of the decay is 29.6 seconds.
But 1/e = 0.367...
So IF the amplitude of this oscillator is decaying exponentially for some crazy reason, then the time constant of the decay is 29.6 seconds.
Given that the amplitude of an oscillator decreases to 36.7% of its initial value in 29.5 s, we want to get the time constant. We will get:
k = 0.041 s^-1
We can write a really simple oscillation equation as:
f(t) = A*cos(k*t)
Where A is the amplitude and k is the time constant.
We know that the amplitude decreases to 36.7% of its initial value to 29.5 seconds, this means that:
f(29.5s) = 0.367*A = A*cos(k*29.5s)
Dividing both sides by A, we get:
0.367 = cos(k*29.5s)
So we just need to solve the above equation for k.
If we use the inverse cosine function in both sides, we get:
Acos(0.367) = Acos(cos(k*29.5s))
Acos(0.367) = k*29.5s
1.195 = k*29.5s
1.195/29.5s = k = 0.041 s^-1
The time constant is:
k = 0.041 s^-1
If you want to learn more, you can read:
https://brainly.com/question/12931896