The position of the particle at time t is
[tex]x(t) = 2.00 \cos (6.00 \pi t+ \frac{2}{5}\pi )[/tex]
If we substitute [tex]t=0.330 s[/tex], we find
[tex]x(0.330 s)=2.00 \cos (6.00 \pi (0.330 s) + \frac{2}{5} \pi)=[/tex]
[tex]=2.00 \cos (1.98 \pi + 0.40 \pi )=2.00 \cos (2.38 \pi) =[/tex]
[tex]=2.00 \cdot (-0.72)=-1.45 m[/tex]
