Answer:
The partial pressure of the oxygen gas in the mixture is 80 mmHg.
Explanation:
Total pressure of the gas mixture ,p = 800 mmHg
Percentage of oxygen gas = 10% = 0.10 =[tex]\chi_{O_2}[/tex]
Percentage of nitrogen gas = 90% = 0.90=[tex]\chi_{N_2}[/tex]
Partial pressure an individual gas in a mixture is given by Dalton's law of partial pressure:
[tex]p_{O_2}=p\times \chi_{O_2}=800 Hg \times 0.10 =80 mmHg[/tex]
[tex]p_{N_2}=p\times \chi_{O_2}=800 Hg \times 0.90 =720 mmHg[/tex]
The partial pressure of the oxygen gas in the mixture is 80 mmHg.
