The overall reaction is:
Br₂(g) + 2 NO(g) ↔ 2 NOBr(g)
rate law = k [Br₂][NO]²
The first step of the overall reaction is:
NO(g) + Br₂(g) K₁⇄⇄K-1 NOBr₂(g)
rate law 1 = k₁ [Br₂][NO] or
rate law 2 = k-1 [NOBr₂]
The second step of the overall reaction is:
NOBr₂(g) + NO(g) →K₂→ 2 NOBr
rate law 3 = k₂[NOBr₂][NO]
So, rate law of overall reaction can be obtained as follows:
(rate law 1)*(rate law 3) / (rate law 2)
= [(k₁[Br₂][NO])* (K₂[NOBr₂][NO])] / k₋₁[NOBr₂]
= [k₁k₂/k₋₁][NO]²[Br₂]
So the correct answer is:
[k₁k₂/k₋₁][NO]² [Br₂]
