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A diver begins on a platform 10 meters above the surface of the water. The diver's height is given by the equation h(t) = −4.9t^2 + 6.5t + 10, where t is the time in seconds after the diver jumps.
How many real solutions does the equation have when the diver's height is 3 m? What are they? Round to the hundredths place.

Respuesta :

carlosego
For this case we have the following equation:
 h (t) = -4.9t ^ 2 + 6.5t + 10
 Substituting the height we have:
 3 = -4.9t ^ 2 + 6.5t + 10
 Rewriting:
 -4.9t ^ 2 + 6.5t + 10 - 3 = 0
 -4.9t ^ 2 + 6.5t + 7 = 0
 Which solutions are:
 t1 = -0.70
 t2 = 2.03
 Answer:
 the equation has 2 real solutions.
 they are:
 t1 = -0.70
 t2 = 2.03

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