Respuesta :
Here are the ratios,
For,
Na⁺¹ and Br⁻¹
1 : 1
So,
NaBr
For,
Al⁺³ and Cl⁻¹
1 : 3
So,
AlCl₃
For,
Mg⁺² and O⁻²
2 : 2
Or, 1 : 1
So,
MgO
For,
Al⁺³ and O⁻²
2 : 3
So,
Al₂O₃
For,
Na⁺¹ and Br⁻¹
1 : 1
So,
NaBr
For,
Al⁺³ and Cl⁻¹
1 : 3
So,
AlCl₃
For,
Mg⁺² and O⁻²
2 : 2
Or, 1 : 1
So,
MgO
For,
Al⁺³ and O⁻²
2 : 3
So,
Al₂O₃
To form the neutral compound, the charge of both the ions present in the reaction will be equal.
The ratio can be determined by balancing the charge.
For NaBr,
Na : Br = 1 : 1
For [tex]\rm AlCl_3[/tex],
[tex]\rm Al^3^+\;:\;Cl^-[/tex] = 1 : 3
For MgO,
[tex]\rm Mg^2^+\;:\;O^2^-[/tex] = 1 : 1
For [tex]\rm Al_2O_3[/tex],
[tex]\rm Al^3^+\;:\;O^2^-[/tex] = 2 : 3
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