The mass of AgCl formed is calculated as follows
write the equation for reaction
that is NiCl2 +2 Ag(No3) ------->Ni(NO3)2 + 2 AgCl
find the moles of NiCl2 used
moles = mass/molar mass
= 0.650/129.69= 5.012 x10^-3 moles
by use of mole ratio between NiCl2 to AgCl which is 2:2 the moles of AgCl is also 5.012 x10^-3 moles
mass = moles x molar mass
mass of AgCl is therefore = ( 5.012 x10^-3) mol x 143.37 g/mol= 0.719 grams
