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What is the electric force acting between two charges of 0.0072 C and -0.0060 C that are 0.0040 m apart?

A. 9.7 10^7 N
B. -9.7 10^7 N
C. -2.4 10^10 N
D. 2.4 10^10 N

Respuesta :

C. Use Coulomb's law F=kq1q2/r^2, where q1 and q2 are the two charges, and r is the distance between the two. Plug in q1=0.0072 C, q2=-0.0060 C, r=0.0040 m, k is the constant 9*10^9 N, F=-2.4*10^10 N, so the answer is C.

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